Base | Representation |
---|---|
bin | 10110010001011001101… |
… | …100100001110000100101 |
3 | 12102022112002121102012001 |
4 | 112101121230201300211 |
5 | 200033442334432323 |
6 | 3131035201325301 |
7 | 215401354365532 |
oct | 26213154416045 |
9 | 5368462542161 |
10 | 1530513202213 |
11 | 5400a5890886 |
12 | 208759936831 |
13 | b1432c06a48 |
14 | 54111d05d89 |
15 | 29c2b0983ad |
hex | 16459b21c25 |
1530513202213 has 4 divisors (see below), whose sum is σ = 1531842928128. Its totient is φ = 1529183476300.
The previous prime is 1530513202199. The next prime is 1530513202223. The reversal of 1530513202213 is 3122023150351.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1530513202213 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1530513202223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 664861231 + ... + 664863532.
It is an arithmetic number, because the mean of its divisors is an integer number (382960732032).
Almost surely, 21530513202213 is an apocalyptic number.
It is an amenable number.
1530513202213 is a deficient number, since it is larger than the sum of its proper divisors (1329725915).
1530513202213 is a wasteful number, since it uses less digits than its factorization.
1530513202213 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1329725914.
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 1530513202213 its reverse (3122023150351), we get a palindrome (4652536352564).
The spelling of 1530513202213 in words is "one trillion, five hundred thirty billion, five hundred thirteen million, two hundred two thousand, two hundred thirteen".
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