153100313 has 2 divisors, whose sum is σ = 153100314. Its totient is φ = 153100312.

The previous prime is 153100243. The next prime is 153100327. The reversal of 153100313 is 313001351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 151117849 + 1982464 = 12293^2 + 1408^2 .

It is a cyclic number.

It is not a de Polignac number, because 153100313 - 2¹² = 153096217 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 153100291 and 153100300.

It is not a weakly prime, because it can be changed into another prime (153100513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76550156 + 76550157.

It is an arithmetic number, because the mean of its divisors is an integer number (76550157).

Almost surely, 2^153100313 is an apocalyptic number.

It is an amenable number.

153100313 is a deficient number, since it is larger than the sum of its proper divisors (1).

153100313 is an equidigital number, since it uses as much as digits as its factorization.

153100313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135, while the sum is 17.

The square root of 153100313 is about 12373.3711251219. The cubic root of 153100313 is about 534.9649879554.

Adding to 153100313 its reverse (313001351), we get a palindrome (466101664).

The spelling of 153100313 in words is "one hundred fifty-three million, one hundred thousand, three hundred thirteen".