Base | Representation |
---|---|
bin | 10110010001111000000… |
… | …101101011001110001011 |
3 | 12102100211122002110121120 |
4 | 112101320011223032023 |
5 | 200041013404023201 |
6 | 3131201534410323 |
7 | 215420115502320 |
oct | 26217005531613 |
9 | 5370748073546 |
10 | 1531023111051 |
11 | 5403376a5945 |
12 | 2088806609a3 |
13 | b14b474b055 |
14 | 5415d91ab47 |
15 | 29c5ac1c536 |
hex | 1647816b38b |
1531023111051 has 64 divisors (see below), whose sum is σ = 2505574342656. Its totient is φ = 811706688000.
The previous prime is 1531023111031. The next prime is 1531023111071. The reversal of 1531023111051 is 1501113201351.
It is an interprime number because it is at equal distance from previous prime (1531023111031) and next prime (1531023111071).
It is a de Polignac number, because none of the positive numbers 2k-1531023111051 is a prime.
It is a super-4 number, since 4×15310231110514 (a number of 50 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (1531023111031) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6953416 + ... + 7170218.
It is an arithmetic number, because the mean of its divisors is an integer number (39149599104).
Almost surely, 21531023111051 is an apocalyptic number.
1531023111051 is a deficient number, since it is larger than the sum of its proper divisors (974551231605).
1531023111051 is a wasteful number, since it uses less digits than its factorization.
1531023111051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 217112.
The product of its (nonzero) digits is 450, while the sum is 24.
The spelling of 1531023111051 in words is "one trillion, five hundred thirty-one billion, twenty-three million, one hundred eleven thousand, fifty-one".
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