Base | Representation |
---|---|
bin | 10110010001111100110… |
… | …010101111010101001001 |
3 | 12102101001010121010111001 |
4 | 112101330302233111021 |
5 | 200041144110030400 |
6 | 3131213434135001 |
7 | 215422064356162 |
oct | 26217462572511 |
9 | 5371033533431 |
10 | 1531102033225 |
11 | 540378200286 |
12 | 2088a2b81461 |
13 | b14c7bc196b |
14 | 5416a1c2769 |
15 | 29c62b0ba6a |
hex | 1647ccaf549 |
1531102033225 has 12 divisors (see below), whose sum is σ = 1898587627456. Its totient is φ = 1224868009680.
The previous prime is 1531102033217. The next prime is 1531102033243. The reversal of 1531102033225 is 5223302011351.
It is not a de Polignac number, because 1531102033225 - 23 = 1531102033217 is a prime.
It is a super-2 number, since 2×15311020332252 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1531102033193 and 1531102033202.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2379484 + ... + 2953666.
Almost surely, 21531102033225 is an apocalyptic number.
It is an amenable number.
1531102033225 is a deficient number, since it is larger than the sum of its proper divisors (367485594231).
1531102033225 is a wasteful number, since it uses less digits than its factorization.
1531102033225 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 680856 (or 680851 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 1531102033225 its reverse (5223302011351), we get a palindrome (6754404044576).
The spelling of 1531102033225 in words is "one trillion, five hundred thirty-one billion, one hundred two million, thirty-three thousand, two hundred twenty-five".
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