Base | Representation |
---|---|
bin | 1000111010011000110… |
… | …0011010100110000001 |
3 | 112122012122110222201212 |
4 | 2032212030122212001 |
5 | 10002033201042443 |
6 | 154201100135505 |
7 | 14030155420235 |
oct | 2164614324601 |
9 | 478178428655 |
10 | 153112127873 |
11 | 59a30893961 |
12 | 25810b37595 |
13 | 11591262743 |
14 | 75a6c245c5 |
15 | 3eb1e21618 |
hex | 23a631a981 |
153112127873 has 2 divisors, whose sum is σ = 153112127874. Its totient is φ = 153112127872.
The previous prime is 153112127827. The next prime is 153112127891. The reversal of 153112127873 is 378721211351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 80286089104 + 72826038769 = 283348^2 + 269863^2 .
It is a cyclic number.
It is not a de Polignac number, because 153112127873 - 214 = 153112111489 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 153112127873.
It is not a weakly prime, because it can be changed into another prime (153112127173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76556063936 + 76556063937.
It is an arithmetic number, because the mean of its divisors is an integer number (76556063937).
Almost surely, 2153112127873 is an apocalyptic number.
It is an amenable number.
153112127873 is a deficient number, since it is larger than the sum of its proper divisors (1).
153112127873 is an equidigital number, since it uses as much as digits as its factorization.
153112127873 is an evil number, because the sum of its binary digits is even.
The product of its digits is 70560, while the sum is 41.
The spelling of 153112127873 in words is "one hundred fifty-three billion, one hundred twelve million, one hundred twenty-seven thousand, eight hundred seventy-three".
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