Base | Representation |
---|---|
bin | 1000111010011000110… |
… | …0011010011011000101 |
3 | 112122012122110221202221 |
4 | 2032212030122123011 |
5 | 10002033201032143 |
6 | 154201100132341 |
7 | 14030155415215 |
oct | 2164614323305 |
9 | 478178427687 |
10 | 153112127173 |
11 | 59a30893385 |
12 | 25810b370b1 |
13 | 11591262325 |
14 | 75a6c24245 |
15 | 3eb1e212ed |
hex | 23a631a6c5 |
153112127173 has 2 divisors, whose sum is σ = 153112127174. Its totient is φ = 153112127172.
The previous prime is 153112127137. The next prime is 153112127243. The reversal of 153112127173 is 371721211351.
Together with previous prime (153112127137) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 82968193764 + 70143933409 = 288042^2 + 264847^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-153112127173 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153112127873) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76556063586 + 76556063587.
It is an arithmetic number, because the mean of its divisors is an integer number (76556063587).
Almost surely, 2153112127173 is an apocalyptic number.
It is an amenable number.
153112127173 is a deficient number, since it is larger than the sum of its proper divisors (1).
153112127173 is an equidigital number, since it uses as much as digits as its factorization.
153112127173 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8820, while the sum is 34.
The spelling of 153112127173 in words is "one hundred fifty-three billion, one hundred twelve million, one hundred twenty-seven thousand, one hundred seventy-three".
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