15311313011 has 2 divisors, whose sum is σ = 15311313012. Its totient is φ = 15311313010.

The previous prime is 15311312987. The next prime is 15311313037. The reversal of 15311313011 is 11031311351.

It is a weak prime.

It is an emirp because it is prime and its reverse (11031311351) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15311313011 is a prime.

It is a super-2 number, since 2×15311313011² (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15311313071) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7655656505 + 7655656506.

It is an arithmetic number, because the mean of its divisors is an integer number (7655656506).

Almost surely, 2^15311313011 is an apocalyptic number.

15311313011 is a deficient number, since it is larger than the sum of its proper divisors (1).

15311313011 is an equidigital number, since it uses as much as digits as its factorization.

15311313011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 135, while the sum is 20.

Adding to 15311313011 its reverse (11031311351), we get a palindrome (26342624362).

The spelling of 15311313011 in words is "fifteen billion, three hundred eleven million, three hundred thirteen thousand, eleven".