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153125240000 = 265437157659
BaseRepresentation
bin1000111010011011111…
…0011011110011000000
3112122020120011011012012
42032212332123303000
510002100030140000
6154202245152052
714030405031065
oct2164676336300
9478216134165
10153125240000
1159a3822a227
12258153bb628
1311593ba39b5
1475a8878c6c
153eb3161735
hex23a6f9bcc0

153125240000 has 280 divisors, whose sum is σ = 393042373680. Its totient is φ = 59125248000.

The previous prime is 153125239997. The next prime is 153125240017. The reversal of 153125240000 is 42521351.

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 232359671 + ... + 232360329.

Almost surely, 2153125240000 is an apocalyptic number.

153125240000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 153125240000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (196521186840).

153125240000 is an abundant number, since it is smaller than the sum of its proper divisors (239917133680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

153125240000 is an equidigital number, since it uses as much as digits as its factorization.

153125240000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 885 (or 860 counting only the distinct ones).

The product of its (nonzero) digits is 1200, while the sum is 23.

Adding to 153125240000 its reverse (42521351), we get a palindrome (153167761351).

The spelling of 153125240000 in words is "one hundred fifty-three billion, one hundred twenty-five million, two hundred forty thousand".