Base | Representation |
---|---|
bin | 10110010010001001001… |
… | …100100100100000010111 |
3 | 12102101120122011121021022 |
4 | 112102021030210200113 |
5 | 200042110343144343 |
6 | 3131250230311355 |
7 | 215430202231655 |
oct | 26221114444027 |
9 | 5371518147238 |
10 | 1531310131223 |
11 | 5404747143a4 |
12 | 2089407b855b |
13 | b152c052b82 |
14 | 54189ab1dd5 |
15 | 29c76015568 |
hex | 16489324817 |
1531310131223 has 2 divisors, whose sum is σ = 1531310131224. Its totient is φ = 1531310131222.
The previous prime is 1531310131207. The next prime is 1531310131237. The reversal of 1531310131223 is 3221310131351.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1531310131223 - 24 = 1531310131207 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1531310131192 and 1531310131201.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1531310139223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765655065611 + 765655065612.
It is an arithmetic number, because the mean of its divisors is an integer number (765655065612).
Almost surely, 21531310131223 is an apocalyptic number.
1531310131223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1531310131223 is an equidigital number, since it uses as much as digits as its factorization.
1531310131223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1620, while the sum is 26.
Adding to 1531310131223 its reverse (3221310131351), we get a palindrome (4752620262574).
The spelling of 1531310131223 in words is "one trillion, five hundred thirty-one billion, three hundred ten million, one hundred thirty-one thousand, two hundred twenty-three".
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