Base | Representation |
---|---|
bin | 10110010010001001001… |
… | …100100100100001111001 |
3 | 12102101120122011121101221 |
4 | 112102021030210201321 |
5 | 200042110343200241 |
6 | 3131250230312041 |
7 | 215430202232155 |
oct | 26221114444171 |
9 | 5371518147357 |
10 | 1531310131321 |
11 | 540474714483 |
12 | 2089407b8621 |
13 | b152c052c29 |
14 | 54189ab2065 |
15 | 29c760155d1 |
hex | 16489324879 |
1531310131321 has 2 divisors, whose sum is σ = 1531310131322. Its totient is φ = 1531310131320.
The previous prime is 1531310131261. The next prime is 1531310131361. The reversal of 1531310131321 is 1231310131351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1483375407721 + 47934723600 = 1217939^2 + 218940^2 .
It is a cyclic number.
It is not a de Polignac number, because 1531310131321 - 27 = 1531310131193 is a prime.
It is not a weakly prime, because it can be changed into another prime (1531310131361) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 765655065660 + 765655065661.
It is an arithmetic number, because the mean of its divisors is an integer number (765655065661).
Almost surely, 21531310131321 is an apocalyptic number.
It is an amenable number.
1531310131321 is a deficient number, since it is larger than the sum of its proper divisors (1).
1531310131321 is an equidigital number, since it uses as much as digits as its factorization.
1531310131321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 810, while the sum is 25.
Adding to 1531310131321 its reverse (1231310131351), we get a palindrome (2762620262672).
The spelling of 1531310131321 in words is "one trillion, five hundred thirty-one billion, three hundred ten million, one hundred thirty-one thousand, three hundred twenty-one".
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