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1531314307 = 5503278269
BaseRepresentation
bin101101101000110…
…0000000010000011
310221201102211022201
41123101200002003
511114004024212
6411541214031
752642646125
oct13321400203
93851384281
101531314307
11716429116
12368a01317
131b5337553
14107535215
158e682b57
hex5b460083

1531314307 has 4 divisors (see below), whose sum is σ = 1531598080. Its totient is φ = 1531030536.

The previous prime is 1531314283. The next prime is 1531314341. The reversal of 1531314307 is 7034131351.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1531314307 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1531324307) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133632 + ... + 144637.

It is an arithmetic number, because the mean of its divisors is an integer number (382899520).

Almost surely, 21531314307 is an apocalyptic number.

1531314307 is a deficient number, since it is larger than the sum of its proper divisors (283773).

1531314307 is an equidigital number, since it uses as much as digits as its factorization.

1531314307 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 283772.

The product of its (nonzero) digits is 3780, while the sum is 28.

The square root of 1531314307 is about 39132.0112823249. The cubic root of 1531314307 is about 1152.6252079358.

Adding to 1531314307 its reverse (7034131351), we get a palindrome (8565445658).

The spelling of 1531314307 in words is "one billion, five hundred thirty-one million, three hundred fourteen thousand, three hundred seven".

Divisors: 1 5503 278269 1531314307