Base | Representation |
---|---|
bin | 11100100001100100… |
… | …11000011011011011 |
3 | 1110112021001020110112 |
4 | 32100302120123123 |
5 | 222330342401001 |
6 | 11011332434535 |
7 | 1051332043454 |
oct | 162062303333 |
9 | 43467036415 |
10 | 15314028251 |
11 | 65494080a5 |
12 | 2b74778a4b |
13 | 15a09190a2 |
14 | a53c0a12b |
15 | 5e9694cbb |
hex | 390c986db |
15314028251 has 2 divisors, whose sum is σ = 15314028252. Its totient is φ = 15314028250.
The previous prime is 15314028239. The next prime is 15314028277. The reversal of 15314028251 is 15282041351.
15314028251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15314028251 - 222 = 15309833947 is a prime.
It is a super-2 number, since 2×153140282512 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15314028221) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7657014125 + 7657014126.
It is an arithmetic number, because the mean of its divisors is an integer number (7657014126).
Almost surely, 215314028251 is an apocalyptic number.
15314028251 is a deficient number, since it is larger than the sum of its proper divisors (1).
15314028251 is an equidigital number, since it uses as much as digits as its factorization.
15314028251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9600, while the sum is 32.
The spelling of 15314028251 in words is "fifteen billion, three hundred fourteen million, twenty-eight thousand, two hundred fifty-one".
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