Base | Representation |
---|---|
bin | 1000111010100000011… |
… | …0011001000111101011 |
3 | 112122021212122111220202 |
4 | 2032220012121013223 |
5 | 10002114342302103 |
6 | 154204201342415 |
7 | 14031024254324 |
oct | 2165006310753 |
9 | 478255574822 |
10 | 153144103403 |
11 | 59a47943615 |
12 | 2581b797a0b |
13 | 11597a79985 |
14 | 75ab18944b |
15 | 3eb4b3a988 |
hex | 23a81991eb |
153144103403 has 4 divisors (see below), whose sum is σ = 153289817208. Its totient is φ = 152998389600.
The previous prime is 153144103397. The next prime is 153144103561. The reversal of 153144103403 is 304301441351.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 304301441351 = 2939 ⋅103539109.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-153144103403 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (153144103103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72855326 + ... + 72857427.
It is an arithmetic number, because the mean of its divisors is an integer number (38322454302).
Almost surely, 2153144103403 is an apocalyptic number.
153144103403 is a deficient number, since it is larger than the sum of its proper divisors (145713805).
153144103403 is a wasteful number, since it uses less digits than its factorization.
153144103403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 145713804.
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 153144103403 its reverse (304301441351), we get a palindrome (457445544754).
The spelling of 153144103403 in words is "one hundred fifty-three billion, one hundred forty-four million, one hundred three thousand, four hundred three".
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