153144354001 has 4 divisors (see below), whose sum is σ = 153156854592. Its totient is φ = 153131853412.

The previous prime is 153144353993. The next prime is 153144354007. The reversal of 153144354001 is 100453441351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100453441351 = 19 ⋅5287023229.

It is a cyclic number.

It is not a de Polignac number, because 153144354001 - 2³ = 153144353993 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (153144354007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6231901 + ... + 6256426.

It is an arithmetic number, because the mean of its divisors is an integer number (38289213648).

Almost surely, 2^153144354001 is an apocalyptic number.

It is an amenable number.

153144354001 is a deficient number, since it is larger than the sum of its proper divisors (12500591).

153144354001 is a wasteful number, since it uses less digits than its factorization.

153144354001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12500590.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 153144354001 its reverse (100453441351), we get a palindrome (253597795352).

The spelling of 153144354001 in words is "one hundred fifty-three billion, one hundred forty-four million, three hundred fifty-four thousand, one".