15320043133141 has 4 divisors (see below), whose sum is σ = 16126361192800. Its totient is φ = 14513725073484.

The previous prime is 15320043133067. The next prime is 15320043133147. The reversal of 15320043133141 is 14133134002351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15320043133141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (15320043133147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 403159029801 + ... + 403159029838.

It is an arithmetic number, because the mean of its divisors is an integer number (4031590298200).

Almost surely, 2^{15320043133141} is an apocalyptic number.

It is an amenable number.

15320043133141 is a deficient number, since it is larger than the sum of its proper divisors (806318059659).

15320043133141 is an equidigital number, since it uses as much as digits as its factorization.

15320043133141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 806318059658.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 15320043133141 its reverse (14133134002351), we get a palindrome (29453177135492).

The spelling of 15320043133141 in words is "fifteen trillion, three hundred twenty billion, forty-three million, one hundred thirty-three thousand, one hundred forty-one".