Base | Representation |
---|---|
bin | 1101111011101111111110… |
… | …1100000010000100001101 |
3 | 2000020120222010002102211002 |
4 | 3132323333230002010031 |
5 | 4002001123114013123 |
6 | 52325550535310045 |
7 | 3140562266552411 |
oct | 336737754020415 |
9 | 60216863072732 |
10 | 15320143110413 |
11 | 4977266432869 |
12 | 1875190b1b325 |
13 | 8718b628201b |
14 | 3ad6dad12d41 |
15 | 1b87a340c528 |
hex | deeffb0210d |
15320143110413 has 2 divisors, whose sum is σ = 15320143110414. Its totient is φ = 15320143110412.
The previous prime is 15320143110379. The next prime is 15320143110469. The reversal of 15320143110413 is 31401134102351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 15241239424009 + 78903686404 = 3904003^2 + 280898^2 .
It is a cyclic number.
It is not a de Polignac number, because 15320143110413 - 222 = 15320138916109 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15320143110113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7660071555206 + 7660071555207.
It is an arithmetic number, because the mean of its divisors is an integer number (7660071555207).
Almost surely, 215320143110413 is an apocalyptic number.
It is an amenable number.
15320143110413 is a deficient number, since it is larger than the sum of its proper divisors (1).
15320143110413 is an equidigital number, since it uses as much as digits as its factorization.
15320143110413 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 29.
Adding to 15320143110413 its reverse (31401134102351), we get a palindrome (46721277212764).
The spelling of 15320143110413 in words is "fifteen trillion, three hundred twenty billion, one hundred forty-three million, one hundred ten thousand, four hundred thirteen".
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