Base | Representation |
---|---|
bin | 11100100010110001… |
… | …10111000010111101 |
3 | 1110112222000201001202 |
4 | 32101120313002331 |
5 | 222340433141013 |
6 | 11012332545245 |
7 | 1051513554335 |
oct | 162130670275 |
9 | 43488021052 |
10 | 15324115133 |
11 | 6554077568 |
12 | 2b78022225 |
13 | 15a2a3b362 |
14 | a552b40c5 |
15 | 5ea4d8858 |
hex | 3916370bd |
15324115133 has 2 divisors, whose sum is σ = 15324115134. Its totient is φ = 15324115132.
The previous prime is 15324115019. The next prime is 15324115189. The reversal of 15324115133 is 33151142351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14645356324 + 678758809 = 121018^2 + 26053^2 .
It is an emirp because it is prime and its reverse (33151142351) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 15324115133 - 224 = 15307337917 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15324115096 and 15324115105.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15324111133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7662057566 + 7662057567.
It is an arithmetic number, because the mean of its divisors is an integer number (7662057567).
Almost surely, 215324115133 is an apocalyptic number.
It is an amenable number.
15324115133 is a deficient number, since it is larger than the sum of its proper divisors (1).
15324115133 is an equidigital number, since it uses as much as digits as its factorization.
15324115133 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5400, while the sum is 29.
Adding to 15324115133 its reverse (33151142351), we get a palindrome (48475257484).
The spelling of 15324115133 in words is "fifteen billion, three hundred twenty-four million, one hundred fifteen thousand, one hundred thirty-three".
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