Base | Representation |
---|---|
bin | 10110010011010000110… |
… | …110101000100101110101 |
3 | 12102111200102100011010221 |
4 | 112103100312220211311 |
5 | 200102041124342331 |
6 | 3132005414014341 |
7 | 215502040650553 |
oct | 26232066504565 |
9 | 5374612304127 |
10 | 1532512340341 |
11 | 540a31299954 |
12 | 2090173473b1 |
13 | b169113ba08 |
14 | 54261618bd3 |
15 | 29ce683a711 |
hex | 164d0da8975 |
1532512340341 has 2 divisors, whose sum is σ = 1532512340342. Its totient is φ = 1532512340340.
The previous prime is 1532512340329. The next prime is 1532512340347. The reversal of 1532512340341 is 1430432152351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 809017498116 + 723494842225 = 899454^2 + 850585^2 .
It is a cyclic number.
It is not a de Polignac number, because 1532512340341 - 29 = 1532512339829 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1532512340297 and 1532512340306.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1532512340347) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 766256170170 + 766256170171.
It is an arithmetic number, because the mean of its divisors is an integer number (766256170171).
Almost surely, 21532512340341 is an apocalyptic number.
It is an amenable number.
1532512340341 is a deficient number, since it is larger than the sum of its proper divisors (1).
1532512340341 is an equidigital number, since it uses as much as digits as its factorization.
1532512340341 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 43200, while the sum is 34.
Adding to 1532512340341 its reverse (1430432152351), we get a palindrome (2962944492692).
The spelling of 1532512340341 in words is "one trillion, five hundred thirty-two billion, five hundred twelve million, three hundred forty thousand, three hundred forty-one".
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