Base | Representation |
---|---|
bin | 100010110110010001111001… |
… | …110010101011111000101011 |
3 | 202002122212021201121220000010 |
4 | 202312101321302223320223 |
5 | 130042032432004224210 |
6 | 1301544203545343003 |
7 | 44165635164565044 |
oct | 4266217162537053 |
9 | 662585251556003 |
10 | 153263656320555 |
11 | 4491a82a465a20 |
12 | 15233634497a63 |
13 | 67699157b4541 |
14 | 29bc0016d78cb |
15 | 12abb15834920 |
hex | 8b6479cabe2b |
153263656320555 has 32 divisors (see below), whose sum is σ = 269218661200128. Its totient is φ = 73836341654400.
The previous prime is 153263656320539. The next prime is 153263656320557. The reversal of 153263656320555 is 555023656362351.
It is not a de Polignac number, because 153263656320555 - 24 = 153263656320539 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 153263656320495 and 153263656320504.
It is not an unprimeable number, because it can be changed into a prime (153263656320557) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2958160861 + ... + 2958212670.
It is an arithmetic number, because the mean of its divisors is an integer number (8413083162504).
Almost surely, 2153263656320555 is an apocalyptic number.
153263656320555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
153263656320555 is a deficient number, since it is larger than the sum of its proper divisors (115955004879573).
153263656320555 is a wasteful number, since it uses less digits than its factorization.
153263656320555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5916373707.
The product of its (nonzero) digits is 72900000, while the sum is 57.
The spelling of 153263656320555 in words is "one hundred fifty-three trillion, two hundred sixty-three billion, six hundred fifty-six million, three hundred twenty thousand, five hundred fifty-five".
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