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153305641141 is a prime number
BaseRepresentation
bin1000111011000110111…
…0100111000010110101
3112122201010121111000221
42032301232213002311
510002432221004031
6154232211534341
714035025306662
oct2166156470265
9478633544027
10153305641141
115a020046284
12258658ba3b1
13115c2388333
1475c47d8a69
153ec3de8a11
hex23b1ba70b5

153305641141 has 2 divisors, whose sum is σ = 153305641142. Its totient is φ = 153305641140.

The previous prime is 153305641133. The next prime is 153305641169. The reversal of 153305641141 is 141146503351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97810060516 + 55495580625 = 312746^2 + 235575^2 .

It is a cyclic number.

It is not a de Polignac number, because 153305641141 - 23 = 153305641133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 153305641097 and 153305641106.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (153305648141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76652820570 + 76652820571.

It is an arithmetic number, because the mean of its divisors is an integer number (76652820571).

Almost surely, 2153305641141 is an apocalyptic number.

It is an amenable number.

153305641141 is a deficient number, since it is larger than the sum of its proper divisors (1).

153305641141 is an equidigital number, since it uses as much as digits as its factorization.

153305641141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 21600, while the sum is 34.

The spelling of 153305641141 in words is "one hundred fifty-three billion, three hundred five million, six hundred forty-one thousand, one hundred forty-one".