Base | Representation |
---|---|
bin | 1101111100011001101000… |
… | …0111110010110111011100 |
3 | 2000021122211022221012011222 |
4 | 3133012122013302313130 |
5 | 4002142022421422134 |
6 | 52335040225032512 |
7 | 3141436333636163 |
oct | 337063207626734 |
9 | 60248738835158 |
10 | 15331324014044 |
11 | 4980a837a0195 |
12 | 1877391485738 |
13 | 87297880892c |
14 | 3b007bc343da |
15 | 1b8c09cd2a2e |
hex | df19a1f2ddc |
15331324014044 has 12 divisors (see below), whose sum is σ = 26832551760168. Its totient is φ = 7664880654000.
The previous prime is 15331324014043. The next prime is 15331324014049. The reversal of 15331324014044 is 44041042313351.
It is a junction number, because it is equal to n+sod(n) for n = 15331324013995 and 15331324014013.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15331324014043) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195294107 + ... + 195372594.
It is an arithmetic number, because the mean of its divisors is an integer number (2236045980014).
Almost surely, 215331324014044 is an apocalyptic number.
It is an amenable number.
15331324014044 is a deficient number, since it is larger than the sum of its proper divisors (11501227746124).
15331324014044 is a wasteful number, since it uses less digits than its factorization.
15331324014044 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 390676516 (or 390676514 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 35.
Adding to 15331324014044 its reverse (44041042313351), we get a palindrome (59372366327395).
The spelling of 15331324014044 in words is "fifteen trillion, three hundred thirty-one billion, three hundred twenty-four million, fourteen thousand, forty-four".
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