153320131 has 2 divisors, whose sum is σ = 153320132. Its totient is φ = 153320130.

The previous prime is 153320117. The next prime is 153320137. The reversal of 153320131 is 131023351.

153320131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 153320131 - 2¹⁷ = 153189059 is a prime.

It is a super-2 number, since 2×153320131² = 47014125139714322, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 153320099 and 153320108.

It is not a weakly prime, because it can be changed into another prime (153320137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76660065 + 76660066.

It is an arithmetic number, because the mean of its divisors is an integer number (76660066).

Almost surely, 2^153320131 is an apocalyptic number.

153320131 is a deficient number, since it is larger than the sum of its proper divisors (1).

153320131 is an equidigital number, since it uses as much as digits as its factorization.

153320131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 19.

The square root of 153320131 is about 12382.2506435623. The cubic root of 153320131 is about 535.2208957677.

Adding to 153320131 its reverse (131023351), we get a palindrome (284343482).

The spelling of 153320131 in words is "one hundred fifty-three million, three hundred twenty thousand, one hundred thirty-one".