Base | Representation |
---|---|
bin | 100010110111010010100110… |
… | …001101110101000001110101 |
3 | 202002220111120211212211012111 |
4 | 202313102212031311001311 |
5 | 130044202213001011013 |
6 | 1302040132521051021 |
7 | 44203644452551336 |
oct | 4267224615650165 |
9 | 662814524784174 |
10 | 153333121110133 |
11 | 44947236531528 |
12 | 15244ba0026a71 |
13 | 6773336099323 |
14 | 29c15111d028d |
15 | 12ad82de7473d |
hex | 8b74a6375075 |
153333121110133 has 16 divisors (see below), whose sum is σ = 160107560781696. Its totient is φ = 146567688664320.
The previous prime is 153333121110121. The next prime is 153333121110163. The reversal of 153333121110133 is 331011121333351.
153333121110133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 153333121110133 - 217 = 153333120979061 is a prime.
It is a super-2 number, since 2×1533331211101332 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 153333121110095 and 153333121110104.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153333121110163) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 269294766 + ... + 269863552.
It is an arithmetic number, because the mean of its divisors is an integer number (10006722548856).
Almost surely, 2153333121110133 is an apocalyptic number.
It is an amenable number.
153333121110133 is a deficient number, since it is larger than the sum of its proper divisors (6774439671563).
153333121110133 is a wasteful number, since it uses less digits than its factorization.
153333121110133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 576684.
The product of its (nonzero) digits is 7290, while the sum is 31.
Adding to 153333121110133 its reverse (331011121333351), we get a palindrome (484344242443484).
The spelling of 153333121110133 in words is "one hundred fifty-three trillion, three hundred thirty-three billion, one hundred twenty-one million, one hundred ten thousand, one hundred thirty-three".
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