Base | Representation |
---|---|
bin | 11100100100000000… |
… | …01010111010100011 |
3 | 1110120200102020212100 |
4 | 32102000022322203 |
5 | 222401102421011 |
6 | 11013341501443 |
7 | 1052000264142 |
oct | 162200127243 |
9 | 43520366770 |
10 | 15334420131 |
11 | 6559975898 |
12 | 2b7b571883 |
13 | 15a4c089a4 |
14 | a567d7759 |
15 | 5eb371d56 |
hex | 39200aea3 |
15334420131 has 12 divisors (see below), whose sum is σ = 22201115040. Its totient is φ = 10199225040.
The previous prime is 15334420109. The next prime is 15334420139. The reversal of 15334420131 is 13102443351.
It is a happy number.
It is not a de Polignac number, because 15334420131 - 227 = 15200202403 is a prime.
It is a super-2 number, since 2×153344201312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 15334420095 and 15334420104.
It is not an unprimeable number, because it can be changed into a prime (15334420139) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1972716 + ... + 1980473.
It is an arithmetic number, because the mean of its divisors is an integer number (1850092920).
Almost surely, 215334420131 is an apocalyptic number.
15334420131 is a deficient number, since it is larger than the sum of its proper divisors (6866694909).
15334420131 is a wasteful number, since it uses less digits than its factorization.
15334420131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3953626 (or 3953623 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 27.
Adding to 15334420131 its reverse (13102443351), we get a palindrome (28436863482).
The spelling of 15334420131 in words is "fifteen billion, three hundred thirty-four million, four hundred twenty thousand, one hundred thirty-one".
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