153354012131 has 8 divisors (see below), whose sum is σ = 165438513504. Its totient is φ = 141609919360.

The previous prime is 153354012121. The next prime is 153354012241. The reversal of 153354012131 is 131210453351.

153354012131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-153354012131 is a prime.

It is a super-2 number, since 2×153354012131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 153354012094 and 153354012103.

It is not an unprimeable number, because it can be changed into a prime (153354012121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 85101215 + ... + 85103016.

It is an arithmetic number, because the mean of its divisors is an integer number (20679814188).

Almost surely, 2^153354012131 is an apocalyptic number.

153354012131 is a deficient number, since it is larger than the sum of its proper divisors (12084501373).

153354012131 is a wasteful number, since it uses less digits than its factorization.

153354012131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 170204301.

The product of its (nonzero) digits is 5400, while the sum is 29.

Adding to 153354012131 its reverse (131210453351), we get a palindrome (284564465482).

The spelling of 153354012131 in words is "one hundred fifty-three billion, three hundred fifty-four million, twelve thousand, one hundred thirty-one".