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1533555132113 is a prime number
BaseRepresentation
bin10110010100001111000…
…000100100011011010001
312102121101002112110112102
4112110033000210123101
5200111210103211423
63132301104410145
7215536632355034
oct26241700443321
95377332473472
101533555132113
1154141698a834
12209268616955
13b17c91ac374
145431dd0501b
1529d58170c28
hex1650f0246d1

1533555132113 has 2 divisors, whose sum is σ = 1533555132114. Its totient is φ = 1533555132112.

The previous prime is 1533555132017. The next prime is 1533555132119. The reversal of 1533555132113 is 3112315553351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1275752178064 + 257802954049 = 1129492^2 + 507743^2 .

It is a cyclic number.

It is not a de Polignac number, because 1533555132113 - 218 = 1533554869969 is a prime.

It is not a weakly prime, because it can be changed into another prime (1533555132119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 766777566056 + 766777566057.

It is an arithmetic number, because the mean of its divisors is an integer number (766777566057).

Almost surely, 21533555132113 is an apocalyptic number.

It is an amenable number.

1533555132113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1533555132113 is an equidigital number, since it uses as much as digits as its factorization.

1533555132113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 101250, while the sum is 38.

The spelling of 1533555132113 in words is "one trillion, five hundred thirty-three billion, five hundred fifty-five million, one hundred thirty-two thousand, one hundred thirteen".