Base | Representation |
---|---|
bin | 100010110111101111101010… |
… | …100000000010001110101011 |
3 | 202010000111010221202010120122 |
4 | 202313233222200002032223 |
5 | 130100210122331121210 |
6 | 1302102333512113455 |
7 | 44206131050540033 |
oct | 4267575240021653 |
9 | 663014127663518 |
10 | 153364331504555 |
11 | 449594a1a30826 |
12 | 1524b05039588b |
13 | 677626b154b32 |
14 | 29c2c322b28c3 |
15 | 12ae558e8db55 |
hex | 8b7bea8023ab |
153364331504555 has 8 divisors (see below), whose sum is σ = 190383308074800. Its totient is φ = 118460725024096.
The previous prime is 153364331504429. The next prime is 153364331504561. The reversal of 153364331504555 is 555405133463351.
153364331504555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 153364331504555 - 28 = 153364331504299 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 153364331504497 and 153364331504506.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 528842522285 + ... + 528842522574.
It is an arithmetic number, because the mean of its divisors is an integer number (23797913509350).
Almost surely, 2153364331504555 is an apocalyptic number.
153364331504555 is a deficient number, since it is larger than the sum of its proper divisors (37018976570245).
153364331504555 is a wasteful number, since it uses less digits than its factorization.
153364331504555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1057685044893.
The product of its (nonzero) digits is 24300000, while the sum is 53.
The spelling of 153364331504555 in words is "one hundred fifty-three trillion, three hundred sixty-four billion, three hundred thirty-one million, five hundred four thousand, five hundred fifty-five".
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