Base | Representation |
---|---|
bin | 100010110111110000010010… |
… | …100110010101000010111011 |
3 | 202010000112212211121210102012 |
4 | 202313300102212111002323 |
5 | 130100213012041240011 |
6 | 1302102524343200135 |
7 | 44206153526660012 |
oct | 4267602246250273 |
9 | 663015784553365 |
10 | 153365004243131 |
11 | 4495980775021a |
12 | 1524b1b974604b |
13 | 677634763a8b5 |
14 | 29c2c97791a79 |
15 | 12ae598078a8b |
hex | 8b7c129950bb |
153365004243131 has 2 divisors, whose sum is σ = 153365004243132. Its totient is φ = 153365004243130.
The previous prime is 153365004243119. The next prime is 153365004243193. The reversal of 153365004243131 is 131342400563351.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-153365004243131 is a prime.
It is a super-2 number, since 2×1533650042431312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (153365004249131) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76682502121565 + 76682502121566.
It is an arithmetic number, because the mean of its divisors is an integer number (76682502121566).
Almost surely, 2153365004243131 is an apocalyptic number.
153365004243131 is a deficient number, since it is larger than the sum of its proper divisors (1).
153365004243131 is an equidigital number, since it uses as much as digits as its factorization.
153365004243131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 41.
The spelling of 153365004243131 in words is "one hundred fifty-three trillion, three hundred sixty-five billion, four million, two hundred forty-three thousand, one hundred thirty-one".
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