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153400035 = 3521314799
BaseRepresentation
bin10010010010010…
…11001011100011
3101200122112021210
421021023023203
5303232300120
623115521203
73541610265
oct1111131343
9350575253
10153400035
1179654798
1243459203
1325a1c669
1416531b35
15d701ce0
hex924b2e3

153400035 has 16 divisors (see below), whose sum is σ = 245606400. Its totient is φ = 81757920.

The previous prime is 153400031. The next prime is 153400141. The reversal of 153400035 is 530004351.

It is not a de Polignac number, because 153400035 - 22 = 153400031 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 153399984 and 153400020.

It is not an unprimeable number, because it can be changed into a prime (153400031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 29566 + ... + 34364.

It is an arithmetic number, because the mean of its divisors is an integer number (15350400).

Almost surely, 2153400035 is an apocalyptic number.

153400035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

153400035 is a deficient number, since it is larger than the sum of its proper divisors (92206365).

153400035 is a wasteful number, since it uses less digits than its factorization.

153400035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6938.

The product of its (nonzero) digits is 900, while the sum is 21.

The square root of 153400035 is about 12385.4767772581. The cubic root of 153400035 is about 535.3138578225.

Adding to 153400035 its reverse (530004351), we get a palindrome (683404386).

The spelling of 153400035 in words is "one hundred fifty-three million, four hundred thousand, thirty-five".

Divisors: 1 3 5 15 2131 4799 6393 10655 14397 23995 31965 71985 10226669 30680007 51133345 153400035