Search a number
-
+
153400315051003 = 236669578915261
BaseRepresentation
bin100010111000010001001011…
…010010010111101111111011
3202010010221000201010200121011
4202320101023102113233323
5130101302321123113003
61302131044252254351
744211543544615516
oct4270211322275773
9663127021120534
10153400315051003
1144972787787869
12152560131713b7
136779784074857
1429c4887285d7d
1512b046305046d
hex8b844b497bfb

153400315051003 has 4 divisors (see below), whose sum is σ = 160069893966288. Its totient is φ = 146730736135720.

The previous prime is 153400315050889. The next prime is 153400315051007. The reversal of 153400315051003 is 300150513004351.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 153400315051003 - 29 = 153400315050491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (153400315051007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3334789457608 + ... + 3334789457653.

It is an arithmetic number, because the mean of its divisors is an integer number (40017473491572).

Almost surely, 2153400315051003 is an apocalyptic number.

153400315051003 is a deficient number, since it is larger than the sum of its proper divisors (6669578915285).

153400315051003 is an equidigital number, since it uses as much as digits as its factorization.

153400315051003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6669578915284.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 153400315051003 its reverse (300150513004351), we get a palindrome (453550828055354).

The spelling of 153400315051003 in words is "one hundred fifty-three trillion, four hundred billion, three hundred fifteen million, fifty-one thousand, three".

Divisors: 1 23 6669578915261 153400315051003