153400315565413 has 4 divisors (see below), whose sum is σ = 175314646360480. Its totient is φ = 131485984770348.

The previous prime is 153400315565411. The next prime is 153400315565447. The reversal of 153400315565413 is 314565513004351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 153400315565413 - 2¹ = 153400315565411 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (153400315565411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10957165397523 + ... + 10957165397536.

It is an arithmetic number, because the mean of its divisors is an integer number (43828661590120).

Almost surely, 2^{153400315565413} is an apocalyptic number.

It is an amenable number.

153400315565413 is a deficient number, since it is larger than the sum of its proper divisors (21914330795067).

153400315565413 is an equidigital number, since it uses as much as digits as its factorization.

153400315565413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 21914330795066.

The product of its (nonzero) digits is 1620000, while the sum is 46.

Adding to 153400315565413 its reverse (314565513004351), we get a palindrome (467965828569764).

The spelling of 153400315565413 in words is "one hundred fifty-three trillion, four hundred billion, three hundred fifteen million, five hundred sixty-five thousand, four hundred thirteen".