Base | Representation |
---|---|
bin | 11100100100101100… |
… | …01110010100011001 |
3 | 1110121002021222001112 |
4 | 32102112032110121 |
5 | 222404042414431 |
6 | 11014105430105 |
7 | 1052100362531 |
oct | 162226162431 |
9 | 43532258045 |
10 | 15340201241 |
11 | 6562164272 |
12 | 2b8149b335 |
13 | 15a6181171 |
14 | a574a04c1 |
15 | 5ebb14c2b |
hex | 39258e519 |
15340201241 has 2 divisors, whose sum is σ = 15340201242. Its totient is φ = 15340201240.
The previous prime is 15340201229. The next prime is 15340201259. The reversal of 15340201241 is 14210204351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11670264841 + 3669936400 = 108029^2 + 60580^2 .
It is a cyclic number.
It is not a de Polignac number, because 15340201241 - 222 = 15336006937 is a prime.
It is a super-2 number, since 2×153402012412 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15340201441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7670100620 + 7670100621.
It is an arithmetic number, because the mean of its divisors is an integer number (7670100621).
Almost surely, 215340201241 is an apocalyptic number.
It is an amenable number.
15340201241 is a deficient number, since it is larger than the sum of its proper divisors (1).
15340201241 is an equidigital number, since it uses as much as digits as its factorization.
15340201241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 960, while the sum is 23.
Adding to 15340201241 its reverse (14210204351), we get a palindrome (29550405592).
The spelling of 15340201241 in words is "fifteen billion, three hundred forty million, two hundred one thousand, two hundred forty-one".
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