Base | Representation |
---|---|
bin | 100010111000010011000010… |
… | …110011111010000110110111 |
3 | 202010011010012110102110212202 |
4 | 202320103002303322012313 |
5 | 130101320423001044231 |
6 | 1302132015244335115 |
7 | 44211644334331451 |
oct | 4270230263720667 |
9 | 663133173373782 |
10 | 153402320331191 |
11 | 44973616700518 |
12 | 1525649284449b |
13 | 6779a1364a389 |
14 | 29c49d77172d1 |
15 | 12b052e1075cb |
hex | 8b84c2cfa1b7 |
153402320331191 has 2 divisors, whose sum is σ = 153402320331192. Its totient is φ = 153402320331190.
The previous prime is 153402320331137. The next prime is 153402320331209. The reversal of 153402320331191 is 191133023204351.
153402320331191 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-153402320331191 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153402320331121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76701160165595 + 76701160165596.
It is an arithmetic number, because the mean of its divisors is an integer number (76701160165596).
Almost surely, 2153402320331191 is an apocalyptic number.
153402320331191 is a deficient number, since it is larger than the sum of its proper divisors (1).
153402320331191 is an equidigital number, since it uses as much as digits as its factorization.
153402320331191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 38.
The spelling of 153402320331191 in words is "one hundred fifty-three trillion, four hundred two billion, three hundred twenty million, three hundred thirty-one thousand, one hundred ninety-one".
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