Base | Representation |
---|---|
bin | 100010111000010011001101… |
… | …100110101000101010011011 |
3 | 202010011010200002010210021222 |
4 | 202320103031212220222123 |
5 | 130101321310324314433 |
6 | 1302132045233322255 |
7 | 44211651663364463 |
oct | 4270231546505233 |
9 | 663133602123258 |
10 | 153402501401243 |
11 | 449736a9934096 |
12 | 1525652340638b |
13 | 6779a42007313 |
14 | 29c4a137acba3 |
15 | 12b053ee72b98 |
hex | 8b84cd9a8a9b |
153402501401243 has 2 divisors, whose sum is σ = 153402501401244. Its totient is φ = 153402501401242.
The previous prime is 153402501401143. The next prime is 153402501401249. The reversal of 153402501401243 is 342104105204351.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-153402501401243 is a prime.
It is not a weakly prime, because it can be changed into another prime (153402501401249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76701250700621 + 76701250700622.
It is an arithmetic number, because the mean of its divisors is an integer number (76701250700622).
Almost surely, 2153402501401243 is an apocalyptic number.
153402501401243 is a deficient number, since it is larger than the sum of its proper divisors (1).
153402501401243 is an equidigital number, since it uses as much as digits as its factorization.
153402501401243 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 57600, while the sum is 35.
Adding to 153402501401243 its reverse (342104105204351), we get a palindrome (495506606605594).
The spelling of 153402501401243 in words is "one hundred fifty-three trillion, four hundred two billion, five hundred one million, four hundred one thousand, two hundred forty-three".
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