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153404034131 is a prime number
BaseRepresentation
bin1000111011011110010…
…1111100110001010011
3112122221222202100211202
42032313211330301103
510003132413043011
6154250044501415
714040331530005
oct2166745746123
9478858670752
10153404034131
115a07063a3a7
122589284a86b
131160988853a
1475d38cc375
153ecc88223b
hex23b797cc53

153404034131 has 2 divisors, whose sum is σ = 153404034132. Its totient is φ = 153404034130.

The previous prime is 153404034103. The next prime is 153404034151. The reversal of 153404034131 is 131430404351.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 153404034131 - 26 = 153404034067 is a prime.

It is a super-2 number, since 2×1534040341312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 153404034094 and 153404034103.

It is not a weakly prime, because it can be changed into another prime (153404034151) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76702017065 + 76702017066.

It is an arithmetic number, because the mean of its divisors is an integer number (76702017066).

Almost surely, 2153404034131 is an apocalyptic number.

153404034131 is a deficient number, since it is larger than the sum of its proper divisors (1).

153404034131 is an equidigital number, since it uses as much as digits as its factorization.

153404034131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8640, while the sum is 29.

Adding to 153404034131 its reverse (131430404351), we get a palindrome (284834438482).

The spelling of 153404034131 in words is "one hundred fifty-three billion, four hundred four million, thirty-four thousand, one hundred thirty-one".