Search a number
-
+
15340403463131 is a prime number
BaseRepresentation
bin1101111100111011011101…
…0011001001001111011011
32000022112021002111222212002
43133032313103021033123
54002314121241310011
652343141205111215
73142210332660215
oct337166723111733
960275232458762
1015340403463131
11498491291671a
1218790a60b850b
13873794885606
143b069da0b5b5
151b908be54c3b
hexdf3b74c93db

15340403463131 has 2 divisors, whose sum is σ = 15340403463132. Its totient is φ = 15340403463130.

The previous prime is 15340403463079. The next prime is 15340403463163. The reversal of 15340403463131 is 13136430404351.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-15340403463131 is a prime.

It is a super-2 number, since 2×153404034631312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15340403460131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7670201731565 + 7670201731566.

It is an arithmetic number, because the mean of its divisors is an integer number (7670201731566).

Almost surely, 215340403463131 is an apocalyptic number.

15340403463131 is a deficient number, since it is larger than the sum of its proper divisors (1).

15340403463131 is an equidigital number, since it uses as much as digits as its factorization.

15340403463131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 38.

Adding to 15340403463131 its reverse (13136430404351), we get a palindrome (28476833867482).

The spelling of 15340403463131 in words is "fifteen trillion, three hundred forty billion, four hundred three million, four hundred sixty-three thousand, one hundred thirty-one".