Base | Representation |
---|---|
bin | 1101111100111011011101… |
… | …0011001001001111011011 |
3 | 2000022112021002111222212002 |
4 | 3133032313103021033123 |
5 | 4002314121241310011 |
6 | 52343141205111215 |
7 | 3142210332660215 |
oct | 337166723111733 |
9 | 60275232458762 |
10 | 15340403463131 |
11 | 498491291671a |
12 | 18790a60b850b |
13 | 873794885606 |
14 | 3b069da0b5b5 |
15 | 1b908be54c3b |
hex | df3b74c93db |
15340403463131 has 2 divisors, whose sum is σ = 15340403463132. Its totient is φ = 15340403463130.
The previous prime is 15340403463079. The next prime is 15340403463163. The reversal of 15340403463131 is 13136430404351.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15340403463131 is a prime.
It is a super-2 number, since 2×153404034631312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15340403460131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7670201731565 + 7670201731566.
It is an arithmetic number, because the mean of its divisors is an integer number (7670201731566).
Almost surely, 215340403463131 is an apocalyptic number.
15340403463131 is a deficient number, since it is larger than the sum of its proper divisors (1).
15340403463131 is an equidigital number, since it uses as much as digits as its factorization.
15340403463131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 155520, while the sum is 38.
Adding to 15340403463131 its reverse (13136430404351), we get a palindrome (28476833867482).
The spelling of 15340403463131 in words is "fifteen trillion, three hundred forty billion, four hundred three million, four hundred sixty-three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •