Base | Representation |
---|---|
bin | 1101111100111011011101… |
… | …0011001001001111011100 |
3 | 2000022112021002111222212010 |
4 | 3133032313103021033130 |
5 | 4002314121241310012 |
6 | 52343141205111220 |
7 | 3142210332660216 |
oct | 337166723111734 |
9 | 60275232458763 |
10 | 15340403463132 |
11 | 4984912916720 |
12 | 18790a60b8510 |
13 | 873794885607 |
14 | 3b069da0b5b6 |
15 | 1b908be54c3c |
hex | df3b74c93dc |
15340403463132 has 48 divisors (see below), whose sum is σ = 39051297919872. Its totient is φ = 4648250182080.
The previous prime is 15340403463131. The next prime is 15340403463163. The reversal of 15340403463132 is 23136430404351.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15340403463131) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2733403 + ... + 6176754.
It is an arithmetic number, because the mean of its divisors is an integer number (813568706664).
Almost surely, 215340403463132 is an apocalyptic number.
15340403463132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
15340403463132 is an abundant number, since it is smaller than the sum of its proper divisors (23710894456740).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15340403463132 is a wasteful number, since it uses less digits than its factorization.
15340403463132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8923218 (or 8923216 counting only the distinct ones).
The product of its (nonzero) digits is 311040, while the sum is 39.
Adding to 15340403463132 its reverse (23136430404351), we get a palindrome (38476833867483).
The spelling of 15340403463132 in words is "fifteen trillion, three hundred forty billion, four hundred three million, four hundred sixty-three thousand, one hundred thirty-two".
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