15342134341 has 2 divisors, whose sum is σ = 15342134342. Its totient is φ = 15342134340.

The previous prime is 15342134333. The next prime is 15342134351. The reversal of 15342134341 is 14343124351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10096029441 + 5246104900 = 100479^2 + 72430^2 .

It is an emirp because it is prime and its reverse (14343124351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15342134341 - 2³ = 15342134333 is a prime.

It is a super-2 number, since 2×15342134341² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15342134321) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7671067170 + 7671067171.

It is an arithmetic number, because the mean of its divisors is an integer number (7671067171).

Almost surely, 2^15342134341 is an apocalyptic number.

It is an amenable number.

15342134341 is a deficient number, since it is larger than the sum of its proper divisors (1).

15342134341 is an equidigital number, since it uses as much as digits as its factorization.

15342134341 is an evil number, because the sum of its binary digits is even.

The product of its digits is 17280, while the sum is 31.

Adding to 15342134341 its reverse (14343124351), we get a palindrome (29685258692).

The spelling of 15342134341 in words is "fifteen billion, three hundred forty-two million, one hundred thirty-four thousand, three hundred forty-one".