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15342555054493 is a prime number
BaseRepresentation
bin1101111101000011011110…
…0010110100000110011101
32000022201211001010011100001
43133100313202310012131
54002333023043220433
652344134505134301
73142314550130302
oct337206742640635
960281731104301
1015342555054493
1149858173920a7
1218795a678a391
13873a48567cb4
143b08256870a9
151b9165cad57d
hexdf4378b419d

15342555054493 has 2 divisors, whose sum is σ = 15342555054494. Its totient is φ = 15342555054492.

The previous prime is 15342555054479. The next prime is 15342555054511. The reversal of 15342555054493 is 39445055524351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 14738020814169 + 604534240324 = 3839013^2 + 777518^2 .

It is a cyclic number.

It is not a de Polignac number, because 15342555054493 - 25 = 15342555054461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15342555054433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7671277527246 + 7671277527247.

It is an arithmetic number, because the mean of its divisors is an integer number (7671277527247).

Almost surely, 215342555054493 is an apocalyptic number.

It is an amenable number.

15342555054493 is a deficient number, since it is larger than the sum of its proper divisors (1).

15342555054493 is an equidigital number, since it uses as much as digits as its factorization.

15342555054493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 32400000, while the sum is 55.

The spelling of 15342555054493 in words is "fifteen trillion, three hundred forty-two billion, five hundred fifty-five million, fifty-four thousand, four hundred ninety-three".