Base | Representation |
---|---|
bin | 1101111101000110000100… |
… | …1101100100110110110111 |
3 | 2000022210121202112212210022 |
4 | 3133101201031210312313 |
5 | 4002340441024130403 |
6 | 52344332120515355 |
7 | 3142341066151514 |
oct | 337214115446667 |
9 | 60283552485708 |
10 | 15343254130103 |
11 | 4986045a5aa39 |
12 | 187976091bb5b |
13 | 873b2a3426c3 |
14 | 3b089046030b |
15 | 1b91a734bd38 |
hex | df461364db7 |
15343254130103 has 2 divisors, whose sum is σ = 15343254130104. Its totient is φ = 15343254130102.
The previous prime is 15343254130063. The next prime is 15343254130181. The reversal of 15343254130103 is 30103145234351.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15343254130103 - 224 = 15343237352887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15343254130903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7671627065051 + 7671627065052.
It is an arithmetic number, because the mean of its divisors is an integer number (7671627065052).
Almost surely, 215343254130103 is an apocalyptic number.
15343254130103 is a deficient number, since it is larger than the sum of its proper divisors (1).
15343254130103 is an equidigital number, since it uses as much as digits as its factorization.
15343254130103 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 35.
Adding to 15343254130103 its reverse (30103145234351), we get a palindrome (45446399364454).
The spelling of 15343254130103 in words is "fifteen trillion, three hundred forty-three billion, two hundred fifty-four million, one hundred thirty thousand, one hundred three".
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