15343300231130 has 8 divisors (see below), whose sum is σ = 27617940416052. Its totient is φ = 6137320092448.

The previous prime is 15343300231121. The next prime is 15343300231211. The reversal of 15343300231130 is 3113200334351.

It can be written as a sum of positive squares in 2 ways, for example, as 14464992004369 + 878308226761 = 3803287^2 + 937181^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×15343300231130² (a number of 27 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 15343300231093 and 15343300231102.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 767165011547 + ... + 767165011566.

Almost surely, 2^{15343300231130} is an apocalyptic number.

15343300231130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

15343300231130 is a deficient number, since it is larger than the sum of its proper divisors (12274640184922).

15343300231130 is a wasteful number, since it uses less digits than its factorization.

15343300231130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1534330023120.

The product of its (nonzero) digits is 9720, while the sum is 29.

Adding to 15343300231130 its reverse (3113200334351), we get a palindrome (18456500565481).

The spelling of 15343300231130 in words is "fifteen trillion, three hundred forty-three billion, three hundred million, two hundred thirty-one thousand, one hundred thirty".