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153445043243 is a prime number
BaseRepresentation
bin1000111011101000001…
…0011000110000101011
3112200001211220211202202
42032322002120300223
510003223412340433
6154254111450415
714041340230052
oct2167202306053
9480054824682
10153445043243
115a0917aa128
12258a4526a0b
131161521649b
1475d9125399
153ed1282ee8
hex23ba098c2b

153445043243 has 2 divisors, whose sum is σ = 153445043244. Its totient is φ = 153445043242.

The previous prime is 153445043231. The next prime is 153445043267. The reversal of 153445043243 is 342340544351.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 153445043243 - 28 = 153445042987 is a prime.

It is a super-2 number, since 2×1534450432432 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 153445043197 and 153445043206.

It is not a weakly prime, because it can be changed into another prime (153445046243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76722521621 + 76722521622.

It is an arithmetic number, because the mean of its divisors is an integer number (76722521622).

Almost surely, 2153445043243 is an apocalyptic number.

153445043243 is a deficient number, since it is larger than the sum of its proper divisors (1).

153445043243 is an equidigital number, since it uses as much as digits as its factorization.

153445043243 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 38.

Adding to 153445043243 its reverse (342340544351), we get a palindrome (495785587594).

The spelling of 153445043243 in words is "one hundred fifty-three billion, four hundred forty-five million, forty-three thousand, two hundred forty-three".