Base | Representation |
---|---|
bin | 1000111011101110001… |
… | …0011001100110010111 |
3 | 112200010121021120111120 |
4 | 2032323202121212113 |
5 | 10003301333300003 |
6 | 154300411135023 |
7 | 14042064165606 |
oct | 2167342314627 |
9 | 480117246446 |
10 | 153470212503 |
11 | 5a0a4a30173 |
12 | 258b0a44473 |
13 | 1161a4b973a |
14 | 75dc5d7a3d |
15 | 3ed35a5853 |
hex | 23bb899997 |
153470212503 has 32 divisors (see below), whose sum is σ = 220532974272. Its totient is φ = 94579968000.
The previous prime is 153470212471. The next prime is 153470212517. The reversal of 153470212503 is 305212074351.
It is not a de Polignac number, because 153470212503 - 25 = 153470212471 is a prime.
It is a super-2 number, since 2×1534702125032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (153470212703) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2145625 + ... + 2215997.
It is an arithmetic number, because the mean of its divisors is an integer number (6891655446).
Almost surely, 2153470212503 is an apocalyptic number.
153470212503 is a deficient number, since it is larger than the sum of its proper divisors (67062761769).
153470212503 is a wasteful number, since it uses less digits than its factorization.
153470212503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71155.
The product of its (nonzero) digits is 25200, while the sum is 33.
Adding to 153470212503 its reverse (305212074351), we get a palindrome (458682286854).
The spelling of 153470212503 in words is "one hundred fifty-three billion, four hundred seventy million, two hundred twelve thousand, five hundred three".
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