Base | Representation |
---|---|
bin | 1000111011111001110… |
… | …0100000100111101011 |
3 | 112200021000002020102111 |
4 | 2032332130200213223 |
5 | 10003401331000133 |
6 | 154305312543151 |
7 | 14043225653413 |
oct | 2167634404753 |
9 | 480230066374 |
10 | 153519000043 |
11 | 5a11a522a52 |
12 | 25905251ab7 |
13 | 1162763bcc6 |
14 | 7604c97643 |
15 | 3ed79e11cd |
hex | 23be7209eb |
153519000043 has 2 divisors, whose sum is σ = 153519000044. Its totient is φ = 153519000042.
The previous prime is 153518999971. The next prime is 153519000083. The reversal of 153519000043 is 340000915351.
It is a happy number.
It is a strong prime.
It is an emirp because it is prime and its reverse (340000915351) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 153519000043 - 225 = 153485445611 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 153518999969 and 153519000014.
It is not a weakly prime, because it can be changed into another prime (153519000083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76759500021 + 76759500022.
It is an arithmetic number, because the mean of its divisors is an integer number (76759500022).
Almost surely, 2153519000043 is an apocalyptic number.
153519000043 is a deficient number, since it is larger than the sum of its proper divisors (1).
153519000043 is an equidigital number, since it uses as much as digits as its factorization.
153519000043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8100, while the sum is 31.
Adding to 153519000043 its reverse (340000915351), we get a palindrome (493519915394).
The spelling of 153519000043 in words is "one hundred fifty-three billion, five hundred nineteen million, forty-three", and thus it is an aban number.
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