Base | Representation |
---|---|
bin | 1101111101100110110010… |
… | …0010111011110100010000 |
3 | 2000100122021122211022102210 |
4 | 3133121230202323310100 |
5 | 4003011431224310021 |
6 | 52352343244312120 |
7 | 3143101501503315 |
oct | 337315442736420 |
9 | 60318248738383 |
10 | 15352034213136 |
11 | 49898410a5305 |
12 | 187b3b1242640 |
13 | 8748c9383cca |
14 | 3b108458ad0c |
15 | 1b951d087e76 |
hex | df66c8bbd10 |
15352034213136 has 20 divisors (see below), whose sum is σ = 39659421717392. Its totient is φ = 5117344737696.
The previous prime is 15352034213093. The next prime is 15352034213149. The reversal of 15352034213136 is 63131243025351.
It is a junction number, because it is equal to n+sod(n) for n = 15352034213094 and 15352034213103.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159917023006 + ... + 159917023101.
Almost surely, 215352034213136 is an apocalyptic number.
15352034213136 is a gapful number since it is divisible by the number (16) formed by its first and last digit.
It is an amenable number.
15352034213136 is an abundant number, since it is smaller than the sum of its proper divisors (24307387504256).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
15352034213136 is a wasteful number, since it uses less digits than its factorization.
15352034213136 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 319834046118 (or 319834046112 counting only the distinct ones).
The product of its (nonzero) digits is 194400, while the sum is 39.
Adding to 15352034213136 its reverse (63131243025351), we get a palindrome (78483277238487).
The spelling of 15352034213136 in words is "fifteen trillion, three hundred fifty-two billion, thirty-four million, two hundred thirteen thousand, one hundred thirty-six".
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