Base | Representation |
---|---|
bin | 1000111011111011001… |
… | …1011001111101110101 |
3 | 112200021102101011200221 |
4 | 2032332303121331311 |
5 | 10003404400031401 |
6 | 154310045334341 |
7 | 14043330662212 |
oct | 2167663317565 |
9 | 480242334627 |
10 | 153525002101 |
11 | 5a122952429 |
12 | 259072673b1 |
13 | 11628960c13 |
14 | 76059bab09 |
15 | 3ed82c97a1 |
hex | 23becd9f75 |
153525002101 has 2 divisors, whose sum is σ = 153525002102. Its totient is φ = 153525002100.
The previous prime is 153525002077. The next prime is 153525002119. The reversal of 153525002101 is 101200525351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 144210822001 + 9314180100 = 379751^2 + 96510^2 .
It is a cyclic number.
It is not a de Polignac number, because 153525002101 - 221 = 153522904949 is a prime.
It is a super-2 number, since 2×1535250021012 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (153525002131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76762501050 + 76762501051.
It is an arithmetic number, because the mean of its divisors is an integer number (76762501051).
Almost surely, 2153525002101 is an apocalyptic number.
It is an amenable number.
153525002101 is a deficient number, since it is larger than the sum of its proper divisors (1).
153525002101 is an equidigital number, since it uses as much as digits as its factorization.
153525002101 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 153525002101 its reverse (101200525351), we get a palindrome (254725527452).
The spelling of 153525002101 in words is "one hundred fifty-three billion, five hundred twenty-five million, two thousand, one hundred one".
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