Base | Representation |
---|---|
bin | 11100100111100011… |
… | …10100100110010110 |
3 | 1110122202110220012012 |
4 | 32103301310212112 |
5 | 222431214310032 |
6 | 11020324224222 |
7 | 1052511441215 |
oct | 162361644626 |
9 | 43582426165 |
10 | 15364213142 |
11 | 6574774813 |
12 | 2b8953b072 |
13 | 15ab13a6a5 |
14 | a5a75107c |
15 | 5edca96b2 |
hex | 393c74996 |
15364213142 has 12 divisors (see below), whose sum is σ = 23489368980. Its totient is φ = 7537158408.
The previous prime is 15364213133. The next prime is 15364213177. The reversal of 15364213142 is 24131246351.
It is a junction number, because it is equal to n+sod(n) for n = 15364213099 and 15364213108.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1361792 + ... + 1373027.
It is an arithmetic number, because the mean of its divisors is an integer number (1957447415).
Almost surely, 215364213142 is an apocalyptic number.
15364213142 is a deficient number, since it is larger than the sum of its proper divisors (8125155838).
15364213142 is an equidigital number, since it uses as much as digits as its factorization.
15364213142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2734927 (or 2734874 counting only the distinct ones).
The product of its digits is 17280, while the sum is 32.
Adding to 15364213142 its reverse (24131246351), we get a palindrome (39495459493).
The spelling of 15364213142 in words is "fifteen billion, three hundred sixty-four million, two hundred thirteen thousand, one hundred forty-two".
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