153661013133 has 4 divisors (see below), whose sum is σ = 204881350848. Its totient is φ = 102440675420.

The previous prime is 153661013101. The next prime is 153661013153. The reversal of 153661013133 is 331310166351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 153661013133 - 2⁵ = 153661013101 is a prime.

It is a super-2 number, since 2×153661013133² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 153661013094 and 153661013103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (153661013153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25610168853 + ... + 25610168858.

It is an arithmetic number, because the mean of its divisors is an integer number (51220337712).

Almost surely, 2^153661013133 is an apocalyptic number.

It is an amenable number.

153661013133 is a deficient number, since it is larger than the sum of its proper divisors (51220337715).

153661013133 is an equidigital number, since it uses as much as digits as its factorization.

153661013133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51220337714.

The product of its (nonzero) digits is 14580, while the sum is 33.

Adding to 153661013133 its reverse (331310166351), we get a palindrome (484971179484).

The spelling of 153661013133 in words is "one hundred fifty-three billion, six hundred sixty-one million, thirteen thousand, one hundred thirty-three".