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15372013 is a prime number
BaseRepresentation
bin111010101000…
…111011101101
31001220222102211
4322220323231
512413401023
61305250421
7244442236
oct72507355
931828384
1015372013
11874a248
125193a11
133252a87
14208208d
151539a0d
hexea8eed

15372013 has 2 divisors, whose sum is σ = 15372014. Its totient is φ = 15372012.

The previous prime is 15371999. The next prime is 15372017. The reversal of 15372013 is 31027351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9597604 + 5774409 = 3098^2 + 2403^2 .

It is an emirp because it is prime and its reverse (31027351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15372013 - 217 = 15240941 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (15372017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7686006 + 7686007.

It is an arithmetic number, because the mean of its divisors is an integer number (7686007).

Almost surely, 215372013 is an apocalyptic number.

It is an amenable number.

15372013 is a deficient number, since it is larger than the sum of its proper divisors (1).

15372013 is an equidigital number, since it uses as much as digits as its factorization.

15372013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 630, while the sum is 22.

The square root of 15372013 is about 3920.7158785099. The cubic root of 15372013 is about 248.6433877283.

Adding to 15372013 its reverse (31027351), we get a palindrome (46399364).

The spelling of 15372013 in words is "fifteen million, three hundred seventy-two thousand, thirteen".