Base | Representation |
---|---|
bin | 10110011010010000011… |
… | …011001111111000010011 |
3 | 12110020001201212120102001 |
4 | 112122100123033320103 |
5 | 200212430431312003 |
6 | 3135250454134431 |
7 | 216156110344636 |
oct | 26322033177023 |
9 | 5406051776361 |
10 | 1540021354003 |
11 | 5441349a6a70 |
12 | 20a572051417 |
13 | b22b9a34672 |
14 | 547749d5c1d |
15 | 2a0d5b9d61d |
hex | 166906cfe13 |
1540021354003 has 4 divisors (see below), whose sum is σ = 1680023295288. Its totient is φ = 1400019412720.
The previous prime is 1540021353971. The next prime is 1540021354019. The reversal of 1540021354003 is 3004531200451.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1540021354003 - 25 = 1540021353971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1540021354073) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 70000970626 + ... + 70000970647.
It is an arithmetic number, because the mean of its divisors is an integer number (420005823822).
Almost surely, 21540021354003 is an apocalyptic number.
1540021354003 is a deficient number, since it is larger than the sum of its proper divisors (140001941285).
1540021354003 is a wasteful number, since it uses less digits than its factorization.
1540021354003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 140001941284.
The product of its (nonzero) digits is 7200, while the sum is 28.
Adding to 1540021354003 its reverse (3004531200451), we get a palindrome (4544552554454).
The spelling of 1540021354003 in words is "one trillion, five hundred forty billion, twenty-one million, three hundred fifty-four thousand, three".
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